Jee advanced strategy 2021 Source :quora Adil Ali Nirban , Mentored A.I.R - 90, 98, 227, 485, 623(JEE,NEET,KVPY) Updated April 10 I hope you did well in JEE Mains and aiming to do great in JEE Advanced as well. If you can work with a proper strategy for the Next two month you can easily get a good rank in JEE Advanced as well. Few important suggestions/strategy for JEE Advanced. Strategy 1 - if you scored 250+ in JEE Mains(I’m assuming you are confident about the theory up to JEE Advanced) Daily you have to do the time-bounded practice of 3hours and after every 3–4 days you need to do time-bounded practice of 6 hours. Re-attempt of important questions(star mark questions) of all the JEE Advanced test which you gave during your last 1–2 years of preparation. DO solve the selective important/star mark questions from your study material and PYQ’s. Proper revision of self-made notes. Do not focus upon any new material in the last 2 months. Strategy 2 - if you scored 250+ in...
Structure of BrF3 Molecule The central atom Br has seven electrons in the valence shell. Three of these will form electron-pair bonds with three fluorine atoms leaving behind four electrons. Thus, there are three bond pairs and two lone pairs. According to VSEPR theory, these will occupy the corners of a trigonal bipyramid. The two lone pairs will occupy the equatorial positions to minimise lone pair -lone pair and the bond pair -lone pair repulsions which are greater than the bond pair-bond pair repulsions. In addition, the axial fluorine atoms will be bent towards the equatorial fluorine in order to minimise the lone-pair lone-pair repulsions. The shape would be that of a slightly bent T.